A sink contains exactly 12 liters of water. If water is drained away from the sink until it holds 6 liters of water less than the quantity drained away, then determine the volume of water that were drained away (in liters)?
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How about this:
x = the water drained away
t h e w a t e r l e f t i n s i n k + t h e w a t e r d r a i n e d a w a y = 1 2 ( x − 6 ) + x = 1 2 x + x = 1 2 + 6 2 x = 1 8 x = 9
thanks @Syed Baqir for the explication
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Equally correct !! NICE
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Maybe You add small explanation for other users , that will be Brilliant my friend !!
I pretty much solved the problem like this, but I don't quite understand where those 6 liters went in this problem. If you took 6 away from the amount that was drained, wouldn't 6 more of those liters also go down the drain along with those 9 liters?
I understand that there is a quantity of water that drained away before the 6 liters drained away at the end but I didn't knew how much is this quantity. When I checked the multiples choices there was just one more than 6 so i choice it.
Check my solution :D
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Water in the sink = 12 (litre)
Water drained away = x
1 2 − x + 6 ≤ x
1 8 ≤ 2 x
x ≥ 1 8 / 2
x ≥ 9
∴ x = 9