Keeping things together can raise a problem!

In a container of negigibe heat capacity, 200 200 g of ice at 0 C 0^{\circ}C and 100 100 g steam at 10 0 C 100^{\circ}C are added to 200 200 g water that has temparture 5 5 C 55^{\circ}C . Assume no heat is lost to the surroundings and the pressure in the container is constant 1.0 1.0 atm. Now if the final temprature of the system and the mass of total water present at this temprature can be represented as A A (in degree Celsius) and B B (in grams), find A + B A+B .

Details and assumptions

Latent heat of fusion for ice = 80 Cal/g 80 \text{ Cal/g} , Latent heat of vaporization for water = 540 Cal/g 540 \text{ Cal/g} and specific heat of water = 1 Cal/(g K) 1 \text{ Cal/(g K)}


The answer is 583.3.

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