Kind of easy... maybe
Next one up is harder!
What is the average of all the digits of ?
(For the pesky know-it-alls: "What is the limit of the average of the first nth digits of , where n goes to infinity?")
The answer is 4.5.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
7 2 repeats the digits 2, 8, 5, 7, 1, and 4, forever. And if you take the first 6 n decimal places and average them (for n an integer), you will get the answer for infinity: 6 n ( 2 + 8 + 5 + 7 + 1 + 4 ) n = 6 2 + 8 + 5 + 7 + 1 + 4 = 4 . 5