Kinetic Energy Basic

The kinetic energy is computed per:

$KE = \frac{1}{2}mv^{2} = \frac{1}{2}(60)(10^{2}) = 3,000 = \boxed{3 kJ}.$

$\large{\mathbf{* KE=\frac{1}{2}mv^2 *}}$

$\boxed{m=60 \text{ kg} \space \space v= 10 \text{ m/s}}$

$\large{\bf{\text{Plug } m \text{ and }v \text{ into }KE=\frac{1}{2}mv^2}}$

$KE=\frac{1}{2}(60)(10 \times 10)=(30)(100)=3000 \text{ joules}$

$1 \text{ kJ} = 1000 \text{ J}$

$\rightarrow 3000 \text{ J} = \boxed{3 \text{ kJ}}$

$\large{\bf{* NOTE:}}$ $\bf{\text{ It's important that } m \text{ and } v \text{ are in the correct SI units (kg and m/s, respectively)}}$

Bruh there are literally sheets full of these types of problems, with thousands of different number values.

$\displaystyle T = \frac{mv^2}{2}$

So energy is $3000J = 3kJ$