Kinetic energy of rotation

A ring of radius 0.5 m 0.5\text{ m} and mass 10 kg 10\text{ kg} is rotating about its diameter with an angular velocity of 20 rad/s . 20\text{ rad/s}. Its kinetic energy is __________ . \text{\_\_\_\_\_\_\_\_\_\_}.

500 J 10 J 100 J 250 J

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Gaurav Agarwal
Oct 28, 2016

K.E. = 1/2Iw^2 =1/2× 1/2 mr^2 × 20^2 Putting associated value K.E.= 250 joules

It is a ring and not a disc. Hence moment of inertia of a body as entered is incorrect. I think the answer has to be 500J.

Sarthak Shiv - 3 years, 7 months ago

Log in to reply

I agree a ring's moment of inertia is m r^2 not 1/2 m*r^2 so the answer is suppose to be 500J.

Ofek Tevet - 1 year, 7 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...