Kirchhoff's Law

Determine I 1 , I 2 I_1, I_2 and I 3 I_3 .

I1 =11A ,I2 = -3A and I3 = 7A I1 =13A ,I2 = 2A and I3 = 12A I1 =14A ,I2 = -2A and I3 = 10A I1 = 8A ,I2 = 1A and I3 = 9A

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1 solution

Check only for the I 2 I_2 part. By Kirchhoff's laww we have,

12 = 14 + I 2 I 2 = 2 12=14+I_2\implies \boxed{I_2=-2}

As one ooption satisfies it that's indeed the correct one, as it is a mcq I am not providing the complete solution.

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