Kitri's Variation, Act II

Kitri and Basilio have managed to flee from the hands of Lorenzo and Gamache and arrived at Port de Barcelona. They are now waiting for a ship to pick them up. As a frequent seafarer and an amateur statistician, Basilio knows that the late time T T of ships arriving at Port de Barcelona follows an exponential distribution with an unknown parameter λ \lambda . From his observations, ships never arrive early, but the probability that a ship arrives within the first 15 minutes after scheduled time is P ( T 15 ) = 0.9 P(T \leq 15) = 0.9 - quite likely for a busy port.

Unfortunately, Kitri and Basilio have been waiting for their ship for an hour. The impulsive Basilio is growing impatient - he is not hopeful that their ship will arrive within the next 15 minutes. The clever Kitri, on the other hand, remains calm. Given that they have been waiting for 1 hour 1 \text{ hour} , Kitri quickly finds that are they going to wait an extra 15 minutes or more \text{extra } 15 \text{ minutes or more} with probability P P .

What is 100 P 100P , rounded to the nearest integer?


The answer is 10.

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1 solution

Huan Bui
Dec 31, 2018

This is a straightforward application of the memoryless property of the exponential distribution, with s = 15 s = 15 and t = 60 t = 60 .

P = P ( T > t + s T > t ) = P ( T > s ) = 1 P ( T s ) = 1 0.9 = 0.1 P = P(T > t+s \vert T > t) = P(T>s) = 1-P(T\leq s) = 1-0.9 = 0.1 . The answer we seek is 100 P = 100 × 0.1 = 10 100P = 100\times 0.1 = \boxed{10} .

Note that P P is independent of t t , how long they have waited for.

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