Knighted!

A graph with 64 nodes represents the squares of a chessboard. The nodes are joined appropriately by edges, each representing a move of the knight. In this graph, every node will be of degree two, three, four, six, or eight. Let the values a , b , c , d a,b,c,d and e e be the number of nodes with each respective degree such that a a is the number of nodes with degree two, b b is the number of nodes with degree three, etc. What is the value of a + c + e ? a+c+e?


The answer is 40.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Geoff Pilling
Nov 5, 2016

Each corner represents a node of degree 2 2 . There are 4 4 of them.

The middle 4 4 on each edge and the four that "connect" those 16 16 diagonally represent nodes of degree 4 4 . There are 20 20 such squares.

The sixteen that are at least 2 2 away from any edge represent nodes of degree 16 16 .

4 + 20 + 16 = 40 4+20+16=\boxed{40}

Lovely solution!

Akeel Howell - 4 years, 7 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...