Know the property?

Algebra Level 3

( n 0 ) ( n 1 ) + ( n 2 ) ( n 3 ) + . . . . . . . . + ( 1 ) r ( n r ) = 28 {n \choose 0 } - {n \choose 1 } + {n \choose 2 } - {n \choose 3 } + ........ + (-1)^{r}{n \choose r } = 28

then n=?


The answer is 9.

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1 solution

Pranjal Jain
Nov 6, 2014

Just guessed it by using the fact that r = 0 n ( 1 ) r ( n r ) = 0 \sum_{r=0}^n (-1)^r\binom{n}{r}=0

First I thought that maybe ( n n 1 ) ( n n ) = 28 \binom{n}{n-1}-\binom{n}{n}=28 which gave n=29 but on substitution, I got it to be -28.

Then I tried ( n n 2 ) ( n n 1 ) + ( n n ) = 28 \binom{n}{n-2}-\binom{n}{n-1}+\binom{n}{n}=28 which gave me n=9.

Luckily this time it was correct! I also found in this process that r=6

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