Korean Mathematics Competition [2000]

Algebra Level 3

2 x + 3 x 4 x + 6 x 9 x = 1 \large 2^x+3^x-4^x+6^x-9^x=1

Find the sum of all real numbers x x satisfying the equation above.


The answer is 0.

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1 solution

Novril Razenda
Jul 3, 2016

Relevant wiki: Real Numbers

2 x + 3 x 4 x + 6 x 9 x = 1 2^x+3^x-4^x+6^x-9^x=1

Setting 2 x = a 2^x=a and 3 x = b 3^x=b , The Equation becomes 1 + a 2 + b 2 a b a b = 0 1+a^2+b^2-a-b-ab=0 Multiplying both sides of the last equation by 2 and completing the squares gives: ( 1 a ) 2 + ( a b ) 2 + ( b 1 ) 2 = 0 (1 - a)^2 + (a - b)^2 + (b - 1)^2 = 0 Therefore 1 = 2 x = 3 x 1=2^x=3^x , so x = 0 x=0 is the only solution

Nicely done!

Hung Woei Neoh - 4 years, 11 months ago

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Thanks :), Hmmm Do you have another solution? :)

Novril Razenda - 4 years, 11 months ago

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Ermmm......nope. I used your method

Hung Woei Neoh - 4 years, 11 months ago

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