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Logic Level 2

There are five houses (1, 2, 3, 4, 5) situating next to each other. Four interviewers (P, Q, R, T) is due to visit one of these houses. Provided that:

  1. One house separated the house P and Q are visiting
  2. Two houses separated the house R and T are visiting
  3. No two interviewers are visiting the same house at any one time.

What house is likely not to be visited by any of the interviewers?

1, 2 and 3 1 and 3 2 and 4 2, 4 and 5 2 and 5 3 and 5 All 5 houses 3 and 4

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1 solution

Vignesh Suresh
Sep 28, 2015

Solution:

According to 1) the possible houses P and Q are visiting are (1,3) , (2,4) and (3,5) .

According to 2) the possible houses R and T are visiting are (1,4) and (2,5) .

Assuming R and T to be visiting (1,4) P and Q cannot visit (1,3) and (2,4) as that would violate 3) therefore only one possible is (3,5) . Therefore in this case the one that is not visited is 2.

Similarly if we take R and T to be visiting (2,5) we get the only house left out as 4.

Hence the solution is 2 and 4.

Very poor English I didn't even understand it.

Hasmik Garyaka - 2 years, 9 months ago

1 pending report

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