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Every day, the 15 students in Mr. Singh's Advanced Chemistry class are randomly divided into 5 lab groups of 3 students each. What is the probability that three of the students - Linda, Martin, and Nancy are in the same lab group today?

1/93 1/91 1/85 1/76

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1 solution

Vishruth Bharath
Jan 16, 2018

Let's use a constructive approach to solving this problem, by looking at the problem from Linda's point of view. We can ask ourselves,"What's the probability that she will be matched with her friends Martin and Nancy?" 2 2 of the other 14 14 students are randomly chosen to be paired with her. There are ( 14 2 ) = 91 \binom {14}{2}=91 ways that this can be done, and only 1 of those ways pairs Martin and Nancy with her. Therefore, the probability is 1 91 \boxed{\frac{1}{91}} .

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