Consider a torus in which the numerical value of its area is the same as the numerical value of its volume.
Evaluate the numerical value of its minor radius.
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Let R be the distance between the center of the torus and the center of the torus' tube and r the radius of the tube AKA minor radius .
It is known that a torus area can be expressed as 4 π 2 R r , where the torus volume can be expressed as 2 π 2 R r 2 .
By solving 4 π 2 R r = 2 π 2 R r 2 , we get r = 2 .