Ladder Ladder on the wall!!!

In triangle ABC,let the ladder be AB=19m and the distance of the foot of the ladder from the wall be AC=x. Now, cos60=x/19 so,x=9.5. That's our solution....

The distance of the foot ladder can be given off by 1/2 hypotenus = $19/2 =9.5$ meters.This is true by the $30,60,90$ special right trianlge.

19 sin 30 *= 19/2= 9.5Write a solution.

Let the distance between the foot of the ladder and the wall be 'd'.

In a right-angled triangle: cosine = adjacent/hypotenuse

Therefore, cos(60) = d/19

d = 19 x 0.5

d = 9.5 metres

Leaning ladder makes a 90° angle, thus forms a right angled triangle, in which the length of ladder is the hypotenuse (19m), angle is 60° and we have to find base. Using trigonometry, cos 30 = x/19, on solving gives 9.5

Consider the Ladder to the wall makes a right angled triangle, then hypotenese = 19m adjacent = ?

cos 60 = adjacent / hypotenese 0.5 = adjacent / 19 therefore, swapping LHS and RHS adjacent = 19 x 0.5 adjacent = 9.5

done....

As angle is 60 deg at base-ladder meet point, hypotenuse is double the base always (By 30-60-90 theorem).

And now, hypotenuse is 19......that means base must be its half!!!!!

i.e. 9.5

cos(60) x 19 gives the length of the distance between the base of the ladder and the base of the house

Let the angle made by ladder with the wall be Δ => Δ= 60° Lenth of ladder=19m

CosΔ=base / hypotenuse

Cos 60°= distance from wall/length of ladder

1/2=d/19

==> d= 9.5m