LADY GAGA JINGLE CONTEST

Probability Level 4

B and C are the only two persons who will enter the LADY GAGA JINGLE CONTEST . Only one entry is allowed per contestant and the judge will declare the one winner as soon as he receives a suitably inane entry , which may be never . B writes inane jingles rapidly but poorly. He has probability 0.7 of submitting his entry first . If C has not already not won the contest, B will be declared the winner with probability 0.3 . C writes slowly, but he has a gift for this sort of thing. If B has not already won the contest by time of C's entry , C will be declared the winner with probability 0.6 ......

x= probability that B wins

y= probability that's C's entry arrived first , given that B wins (only for this case)

z= probability that first entry wins the contest

FIND .... x+y+z....

(Enter answer upto 3 decimal places)

THIS IS MY FIRST PROBLEM SO PLEASE SHARE IT ... 😀.....

The answer is 0.782.

2 solutions

Mohit Kuri
Apr 24, 2015

Also you may confirm your values of x , y , z that

x=0.246

y=0.146

z=0.39

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How did you get Y?

I figure that

Chances of C entering first= .3

....and failing= .4

...and B winning next= .3

.3 * .3 * .4=0.036

Alex Li - 5 years, 9 months ago

Rohit Sachdeva
Apr 24, 2015

x= P(B wins)=P(B-1)xP(B win) + P(C-1)xP(C lose)xP(B win) = 0.7x0.3+0.3x0.4x0.3 = 0.246

y=P(C-1/B wins) = 0.3x0.4x0.3/x = 0.146 0.3x0.6 =0.39

z=P(B-1)xP(B win) + P(C-1)xP(C win) = 0.7x0.3 +

x+y+z = 0.782

LADY GAGA JINGLE CONTEST

The answer is 0.782.

2 solutions

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