Large Modulo

Level 2

What is the remainder when 222 2 5555 2222^{5555} is divided by 7 7 ?


The answer is 5.

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1 solution

Jubayer Nirjhor
Dec 23, 2013

222 2 5555 3 5555 ( m o d 7 ) 2222^{5555}\equiv 3^{5555} \pmod{7}

3 ( 7 1 ) = 3 6 1 ( m o d 7 ) [ Fermat’s Little Theorem ] 3^{(7-1)}=3^6\equiv 1\pmod{7} ~~~~~~~~~~~[\text{Fermat's Little Theorem}]

3 5555 = 3 5550 3 5 = ( 3 6 ) 925 3 5 1 925 3 5 = 3 5 = 243 5 ( m o d 7 ) 3^{5555}=3^{5550}\cdot 3^{5}=\left(3^6\right)^{925}\cdot 3^5\equiv 1^{925}\cdot 3^5=3^5=243\equiv 5\pmod{7}

222 2 5555 5 ( m o d 7 ) \therefore ~~~ 2222^{5555} \equiv \fbox{5} \pmod{7}

could anyone tell me what those 3 dots at the end of this proof mean?

mathh mathh - 6 years, 10 months ago

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Therefore

Good pic....

ashutosh mahapatra - 6 years, 10 months ago

It means Therefore.

A Former Brilliant Member - 6 years, 10 months ago

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