Large Primes are difficult to find !!!

Find the number of primes p p such that

1999 ! + 1 < p < 1999 ! + 1999. 1999!+1<p<1999!+1999.


The answer is 0.

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1 solution

Curtis Clement
Aug 19, 2015

For 1999 ! + n \ 1999! +n (1 < n < 1999) n is a factor of the whole expression, leaving no primes in the given range. In fact a similar expression can be used to show that generally consecutive primes get further and further apart as they get larger.

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