JEE Piston's paradoxes

Two piston with masses and cross-section as shown . After an explosion in the space b/w the piston , the pistons fly out of pipes.Velocity of left piston is given in diagram. Then How fast is 2nd piston moving? Chose correct matching .

C a s e ( i ) Case(i) : If pipe is fixed and can not move .

1 ) m 1 v m 2 , 2 ) S 2 v S 1 , 3 ) m 1 S 1 v m 2 S 2 , 4 ) m 1 S 2 v m 2 S 1 \displaystyle{1)-\cfrac { { m }_{ 1 }v }{ { m }_{ 2 } } ,2)-\cfrac { { S }_{ 2 }v }{ { S }_{ 1 } } ,3)-\cfrac { { m }_{ 1 }{ S }_{ 1 }v }{ { m }_{ 2 }{ S }_{ 2 } } ,4)-\cfrac { { m }_{ 1 }{ S }_{ 2 }v }{ { m }_{ 2 }{ S }_{ 1 } } }

C a s e ( i i ) Case(ii) If pipe is not fixed and its total mass is M ?Neglect any friction between the piston and tube wall.

1 ) m 1 v m 2 + M , 2 ) S 2 v S 1 , 3 ) m 1 S 1 v m 2 S 2 + M ( S 2 S 1 ) , 4 ) m 1 S 2 v m 2 S 1 + M ( S 2 S 1 ) \displaystyle{1)-\cfrac { { m }_{ 1 }v }{ { m }_{ 2 }+M } ,2)-\cfrac { { S }_{ 2 }v }{ { S }_{ 1 } } ,3)-\cfrac { { m }_{ 1 }{ S }_{ 1 }v }{ { m }_{ 2 }{ S }_{ 2 }+M({ S }_{ 2 }-{ S }_{ 1 }) } ,4)-\cfrac { { m }_{ 1 }{ S }_{ 2 }v }{ { m }_{ 2 }{ S }_{ 1 }+M({ S }_{ 2 }-{ S }_{ 1 }) } }

Answer as the sum of two values of respective options.

For example, if you got answer as option 1 in case (i) and option 2 in case (ii) then your answer is 1+2 = 3.


The answer is 7.

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1 solution

Harsh Shrivastava
Jan 21, 2017

@shubham dhull please help, I could not solve case 2.

solved without pen , paper in the first attempt :P sorry for replying so late , was busy with clasien condensation :P you may see it too.... "https://www.youtube.com/watch?v=Amc9FKASjt8y ", See the concept is that since the pipe will move too and the momentum must remain conserved , you must consider the movement of the pipe too in ur euations and assume it's velocity in any direction (along the line of motion of pipe) and the conserve momentum , you should get it :)

A Former Brilliant Member - 4 years, 4 months ago

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