A square and a rectangle have equal areas. Which has a larger perimeter?
Note: Assume that the square and rectangle are not congruent (square has four equal sides and rectangle has two longer sides and two short sides)
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Let each side of the square be of a units. Let the rectangle have length l and breadth b .
Given: a 2 = l × b
Just plug in some values that satisfy the given condition. For example;
a = 2 , l = 4 and b = 1
Now substitute these values in their respective perimeter formulas and you'll get a straight answer.