Larger than

Level pending

If $f(x) = \frac{x-1}{x-1}$ while $x$ is a positive integer and $x$ must be larger than $n$ to get a real solution

What is $n$ ?

1 solution

Daniel Lim
Jan 10, 2014

$x$ must be positive to satisfy the solution

So we assume that $x = 1$ , $f(1) = \frac{1-1}{1-1} = \frac{0}{0}$

$\frac{0}{0}$ is undefined, so $x$ cannot be $1$

$x$ must be larger than 1 to get a real solution

Therefore, $\boxed{n = 1}$