Largest Possible Circle in a Cube

Geometry Level 3

Given a cube of edge length s s , the radius of the largest circle that can be drawn inside the cube is given by

r = s a b r = s \sqrt{ \dfrac{a}{b} }

where a , b a,b are positive coprime integers. Find a + b a + b .


The answer is 11.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The circle can be inscribed in a regular polygon and the largest regular polygon that can be inscribed in the cube is a regular hexagon which vertices are midpoints of the edges of the cube (one such hexagon is shown on the figure). The radius R R of the circle is the apothem O M OM of the hexagon. Hence, R = O M = 3 2 K L = 3 2 ( 1 2 E G ) = 3 2 ( 1 2 s 2 ) = s 3 8 R=OM=\frac{\sqrt{3}}{2}KL=\frac{\sqrt{3}}{2}\left( \frac{1}{2}EG \right)=\frac{\sqrt{3}}{2}\left( \frac{1}{2}s\sqrt{2} \right)=s\sqrt{\frac{3}{8}} For the answer, a + b = 3 + 8 = 11 a+b=3+8=\boxed{11} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...