Determine the biggest possible value of for which the equation has unique solution in natural numbers.
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If ( x , y ) is a solution, then so is ( x − 2 0 0 7 , y + 2 0 0 5 ) and ( x + 2 0 0 7 , y − 2 0 0 5 ) . So for ( x , y ) to be unique, we must have x − 2 0 0 7 ≤ 0 and y − 2 0 0 5 ≤ 0 . The largest such ( x , y ) is ( 2 0 0 7 , 2 0 0 5 ) , which leads to k = 2 0 0 5 ⋅ 2 0 0 7 ⋅ 2 = 8 0 4 8 0 7 0 .