Last Digit Of $n^n$ Summation (Part 2)

Number Theory Level 5

$\large 1^1 + 2^2 + 3^3 + \dots + 100^{100}$

Find the last two digits of the number above.

The answer is 20.

1 solution

Giorgos K.
Feb 22, 2018

Mathematica

Sum[n^n, {n, 100}]

100371115746176445351701210713361941528546861949073514542015172437236580034634746971244943788132460150776779198800002366059871900041784732217539059306483834977865973576751345853385981719448969027641920

Last Digit Of n n n^n n n Summation (Part 2)

The answer is 20.

1 solution

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Last Digit Of $n^n$ Summation (Part 2)