Lazy Worker?

Classical Mechanics Level 1

A worker used $650N$ constantly for $2$ minutes in an attempt to move a mountain, but unfortunately for them, $\mathbf{\color{#D61F06} the}$ $\mathbf{\color{#D61F06} mountain}$ $\mathbf{\color{#D61F06} remained}$ $\mathbf{\color{#D61F06} stationary}$ . How much work did they do? $\\$

$\mathbf{\large Assumptions}$ $\:$ $\mathbf{\large And}$ $\:$ $\mathbf{\large Details:}$ $\\$ $\cdot$ Answer in Joules ( newton-metres ) $\\$ $\cdot$ Round the answer to the nearest integer

The answer is 0.

4 solutions

§Martie On Brilliant
Jun 9, 2020

The formula for work is ${\color{#D61F06} W}$ ${\color{#D61F06} =}$ ${\color{#D61F06} F}$ ${\color{#D61F06} \times}$ ${\color{#D61F06} d}$ . If the object receiving force (the mountain) does not move, there is no work done, as $x$ $\times$ $0$ $=$ $0$ . If there is no work done, then there are no Joules of work, hence the answer is $\boxed{{\color{#20A900} 0}}$ . $\\$

In the equation, assume 'W' is work, 'F' is force applied, and 'd' is the distance the object moves.

§martie On Brilliant - 1 year ago

Callie Ferguson
Jun 11, 2020

A great metaphor for how my life is going right now. "You tried, but you technically didn't do any work." Lol

Vinayak Srivastava
Jun 10, 2020

Work done $=$ Force applied $\times$ Displacement in the direction of force

Since Displacement in the direction of force $=0$ ,

Work done $=$ $650 N$ $\times$ $0$ $=\boxed{0}$

Mahdi Raza
Jun 9, 2020

$\text{Work }= \text{ Force } \times \text{ Displacement }$

Here the displacement is $0$ , thus the Work done will also be $\boxed{0}$

Lazy Worker?

The answer is 0.

4 solutions

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