LCM addiction

If
A=997! and
B=1001 *1002 *1003 *1004 *1005 *1006.
Lcm of A and B is k!.
Find the value of k?


The answer is 997.

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2 solutions

Kay Xspre
Nov 15, 2015

B can be written as the following.

b = ( 143 × 7 ) × ( 167 × 6 ) × ( 59 × 17 ) × ( 251 × 4 ) × ( 67 × 15 ) × ( 2 × 503 ) b = (143\times7)\times(167\times6)\times(59\times17)\times(251\times 4)\times(67\times15)\times(2\times503)

Or simply rearranging to b = 2 × 4 × 6 × 7 × 15 × 17 × 59 × 67 × 143 × 167 × 251 × 503 b = 2\times4\times6\times7\times15\times17\times59\times67\times143\times167\times251\times503

As we realized that a = 997 ! = 1 × 2 × 3 × 4 × × 997 a = 997! = 1\times2\times3\times4\times\dots\times997 , a a will contain all factors in b b , and thus, a a is the LCM for A and B.

Abhishek Singh
Nov 14, 2015

Since none of the 6 numbers in B is prime....So,the answer of LCM is 997! ..But this method doesn't work in the case of repeating factors as contradicted by Mr. Harish Sasikumar.

That cannot be the complete solution. Let's say when A=5! and B= 10 × 9 × 8 10\times9\times8 , LCM is not 5! eventhough none of the 3 numbers in B is a prime.

Harish Sasikumar - 5 years, 7 months ago

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