7 2 2 , π
Find the lowest common multiple (L.C.M.) of the given above two numbers ?
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Now 600 points today
If LCM of a and b is L , then L = a × n = b × m where n and m are integers.
Now if LCM of 7 2 2 and π exists then π = 7 2 2 × m n . But this can't be true as π is an irrational number and 7 2 2 × m n is rational. Our assumption was wrong therefore LCM of 7 2 2 and π does not exist.
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@Sandeep Bhardwaj u put up 4 questions with same answers any ways i earned 400 points , anyways keep posting