leap year

What is the probability (to two decimal places) that a non leap year should have 53 sundays?


The answer is 0.14.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Rohit Sharma
Oct 4, 2014

Every year has 52 weeks and one day is extra, suppose the first year has a 53rd Monday, therefore 7 years after that it'll be a Sunday. Thus the probability is 1\7 ~ 0.14

If the year begins on a Sunday that extra would be sunday ie 53rd Sunday. So it is the probability of the year starting on a Sunday or One of the 7 days.

Praviv Vivpra - 6 years, 8 months ago
Siddharth Pandit
Oct 20, 2014

a non leap year has 365 days. the day with which the year starts comes 53 times in that year .An year can start with any one of the 7 days.Therefore the probablity of the year starting with a sunday is 1/7.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...