Learning Laws of Thomas Graham by solving this (1) =)

Chemistry Level 2

Let set that they have the same condition. The rate of diffusion of hydrogen gas is 4 times bigger than the rate of diffusion of gas X , so What is the MOLAR MASS of gas X?

You can solve this question by using:

(velocity of Hydrogen)^2 / (velocity of Oxygen)^2 = (Molar mass of oxygen / Molar mass of Hydrogen)

What is this law talking about ?

-The rate of effusion of a gas is inversely proportional to the square root of either the density or the molar mass of the gas.

64 32 18 16

Nicole Ling by Nicole Ling , 24, Malaysia

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1 solution

Nicole Ling
Jan 28, 2014

(velocity of Hydrogen)^2 / (velocity of Oxygen)^2 = (Molar mass of oxygen / Molar mass of Hydrogen)

Molar mass of Oxygen = Molar mass of Hydrogen x (velocity of Hydrogen)^2 / (velocity of Oxygen)^2 

                                     = 2 x (4 / 1)^2
                                     = 32
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