Learning Laws of Thomas Graham by solving this (2) =)

Chemistry Level 2

If equal amounts of HELIUM and ARGON are placed in a porous container and allowed to escape, which gas will escape faster and how much faster?

terms : The molecular weight of He = 4.00 The molecular weight of Ar = 39.95

Graham's Law is: rate 1 / rate 2 = √Molar Mass2 / √Molar Mass1

0.1 9.99 3.16 0.316

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1 solution

Nicole Ling
Jan 28, 2014

Set rate1 = He = x Set rate2 = Ar = 1

The molecular weight of He = 4.00
The molecular weight of Ar = 39.95

Graham's Law is:

r1 over r2 = √MM2 over √MM1

Substituting, we have:

x / 1 = √(39.95 / 4.00)

x = 3.16 times as fast.

so Gas of He is 3.16 times faster than gas of Ar

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