Least!

Read the following statements carefully.

[ 1 ] [1] . Any non-empty set of integers has a least element.

[ 2 ] [2] . Any non-empty finite set of real numbers has a least element.

[ 3 ] [3] . Any non-empty finite set of complex numbers has a least element.

Which of these statements are correct?


This problem is from the set "MCQ Is Not As Easy As 1-2-3". You can see the rest of the problems here .
Only [ 2 ] [2] Only [ 1 ] [1] [ 1 ] [1] and [ 2 ] [2] None of them are correct.

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1 solution

Somdutt Goyal
Sep 30, 2014

1) Take set of negative integers. It is a non empty subset of integers and does not has a least element. 2) Since we have order property in real numbers, we can arrange the finite number of elements in ascending order and then can choose the least one. 3) But we don't have order property in complex number. So we cannot even compare two element.

why can't we consider a -ve Infinitive a least quantity??

Arun Jp - 6 years, 8 months ago

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-\infty is not a negative integer.

Ivan Koswara - 6 years, 4 months ago

Because...for some dumb reason, -\infty is either greater than, less than, or equal to -\infty . One of the three, but not more than one at the same time.

Trevor Arashiro - 6 years, 7 months ago

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