Katie is teaching a class of thirty pupils, of which fourteen are girls. She knows that there are twenty-two pupils who are right-handed.
What is the minimum number of girls who are right-handed in this class?
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22-16(boys) = 6 (mim girls)
I got it!!!!!!
Your Ans Is according to Probability. But Simply If We Solve Like....Totall=30➡14 girls➡22 Right.handed So...16 boys out of 30 then Remove this Boys From Right hand Crew And Rest Of Them..Are Girls=6😂
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Probability? Where does this answer even mention that?
I go it!!!
So, basically you are saying 30-14=16, 22-16=6, right? if so, THAT'S HOW I DID IT!!!
I did it this way. There are 8 left-handed students, so the min number of right-handed girls is 14-8=6.
Total no. of pupils = 30 No. of girls = 14 No' of right handed pupils = 22 So, no. of left handed pupils = 30 - 22 = 8 Suppose if all the 8 left handed pupils are girls then , no. of right handed girls will be = 14 - 8 = 6
22(total no of right handed pupils)-16(boys)=6(no of girls)
total = 30. no.of girls = 14, no.of boys = 16, total no.of right handed = 22. therefore minimum no.of right handed girls = no.of right handed - no.of boys.that is = 6
No. of girls=14 No. of boys=16 Maximum no. of right handed pupils who are boys=16 Therefore, required answer=(22-16)=6
Suppose that all boy are right-handed, thus the minimum number of girls who are right-handed are 22 - 16 = 6
Number of girls in the class= 14
Number of boys in the class= 16
Number of right-handed students= 22
Number of left-handed students= 8
for minimum number of right-handed girls, maximum number of boys need to be right handed.
Since the number of boys is 16 and number of right-handed students are 22 the maximum number of right handed boys are 16 itself since maximum all boys can be right handed out of the 22 right-handed students.
so there are 22-16= 6 right-handed girls at minimum.
Therefore the minimum number of right handed girls are 6
Easy: 14 Girls and 16 boys so the intersection of these groups are 14-8+16-8+6=20 so there are 14-8 = 6 and the 8 is 16-8 and then group it and gave us 20 so B(14) and G(6).
there are 14 girls, 16 boys, 22 right-handed, and 8 left-handed.
to get the least number of right-handed girls, we let all those boys to be right-handed, leaving us with right handed girl = 22-16 = 6
RHgirls = 30(all pupils) - 8 (all LH pupils) - RHboys. RHgirls is on minimun when RHboys are on maximum (all of them = 16). So RHgirsl (min) = 30-8-16 = 6
Should we really ignore the multigender and the ambidextrous?
Period.
There could be multigender and ambidextrous people in the class, but that wouldn't change the result. If anything, you assumed their absence, but it wasn't stated.
students: 30
girls :14 (this includes any multigender people who have girl as one of their gender)
right handed : 22 (this includes any ambidextrous people: we're interpreting the term as 'can write comfortably with the right hand')
non girls: 26 (this includes boys, agendered, and multigenders whose genders do not include girl)
non right handed: 8 (lefties and people that can't write)
minimum number of right handed girls = 14+22-30=6, because how many girls, right handed people and students there are is sufficient to determine the least number of right handed girls.
if you interpret any term differntly (like 'right-handed' as 'writes comfortably with the right hand'), the number of 'right handed girls' doesn't change. Only what you mean by 'right handed' and 'girl', and therefore by 'right handed girl', changes.
Still, you have a point for all the solutions that label 'non girls' as 'boys' and all 'non right handed people' as 'left handed people' (they are adding two assumptions, which may or may not hold for the class: non girl=boy, non right handed= left handed, assumptions which are probably true in their direct experience as far as they know, but can't be assumed in abstract).
The question is fine though, since the answer doesn't change depending on your assumptions.
We know that the number of the pupils in the class is 30 we know that the number of right-handed pupils are 22 so left-handed pupils in the class are 30-22=8. Then we know that the number of the girls in the class are 14. So we have 14-8=6. So the correct answer is 6.
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Number of girls in the class is 14.
Number of left-handed pupils + Number of right-handed pupils = 30. So,
Number of left-handed pupils + 22 = 30,
Number of left-handed pupils = 8.
Therefore, the minimum number of right-handed girls is 1 4 − 8 = 6 .