Length increases, Diameter decreases,then resistance?

The length of a given cylindrical wire is increased by 100% . Due to the consequent, there is d e c r e a s e \color{#456461}{decrease} in diameter.

The change in the r e s i s t a n c e \color{#0C6AC7}{resistance} of the wire will be

50% 200% No change 400% 100% 300%

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2 solutions

Saurabh Meena
Aug 18, 2015

sol sol

Rwit Panda
Sep 25, 2015

We have the length doubled but the total volume of the part of the error remains same. So (cross sectional area)*(length) is constant. As length is doubled so area is halved. Now, as resistance is proportional to L/A, so new resistance is 2L/A/2 = 4L/A. So it is increased by 300%. Ola!!!!

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