A circular hoop is to be supported in a horizontal position 6 inches away from a vertical wall by a pair of horizontal bars at right angle to the wall, each reaching to the outer rim of the hoop. A second pair of bars reinforces these. It is placed directly above the first pair and goes from the wall to the closer rim of the hoop, as pictured. Find the amount of material needed for the bars, that is the total length of all four bars, in inches.
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The image above is a view from the top.
The distance of the hoop from the wall, K M = 6 , the diameter of the circle M N = 1 7 × 2 = 3 4
The shorter bar at the top of the image has the length L s h o r t = A C = 6 + B C
The longer bar at the top has a length L l o n g = A D = 6 + 3 4 − D E
But because B C = D E , this is also L l o n g = 4 0 − B C
The sum of the two lengths is therefore L = L s h o r t + L l o n g = 6 + B C + 4 0 − B C = 4 6
Analogous calculation can be done for the pair of bars below, F H and F I , which while not necessarily the same lengths as A C and A D , also add up to 4 6 .
The total length of all four bars is therefore 4 6 × 2 = 9 2 inches.