Let Euler count!

Geometry Level pending

A convex polyhedron P P has 47 47 faces, 35 35 of which are triangles, 5 5 of which are quadrilaterals, and 7 7 of which are pentagons. How many vertices does P P have?


The answer is 35.

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1 solution

Marta Reece
Mar 28, 2017

The number of vertices V V , faces F F , and edges E E in a convex 3-dimensional polyhedron, satisfy V + F E = 2 V+F-E=2 . This fact is known as Euler's formula.

In this case F = 47 F=47 and E = 1 2 ( 35 × 3 + 5 × 4 + 7 × 5 ) = 80 E=\frac{1}{2}(35\times3+5\times4+7\times5)=80 so V = 2 + 80 47 = 35. V=2+80-47=35.

Suppose if we take a triangle and two of its edges are borrowed by a quadrilateral, then don't we overcount the number of edges?

Anmol Shetty - 4 years, 1 month ago

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We are talking about polyhedrons, with flat faces. That excludes the possibility of having two of the faces sharing two edges.

Marta Reece - 4 years, 1 month ago

Oh I get it thank you very much.

Anmol Shetty - 4 years, 1 month ago

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