You are making a recipe that consists of 5 different ingredients. In how many different orders can you add the ingredients to the bowl?
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Le answer is le 120
There are
5
different ingredients.
At first we have
5
options to add ingredients.Secondly we have
4
options to add ingredients.Thirdly we have
3
options to add ingredients.Fourthly we have
2
options to add ingredients.At last we have
1
option to add ingredient.
So,We can add ingredients (
5
×
4
×
3
×
2
×
1
) different orders.
SO,The answer is
5
!
=
1
2
0
we can directly use the formula nPr for this question :(.....
amazing :)
The answer is 5 ! = 1 2 0
the answer is 5! = (5 x 4 x 3 x 2 x 1) = 120
Since,a recipe is constituted with 5 ingredients,1st ingredient can be chosen in 5 different ways,second one in 4 ways,third one in 3 ways,fourth one in 2 ways and last one in a unique way.....thus altogether,5.4.3.2.1=120
There are 5 different ingredients.
So, The number of different orders can add the ingredients to the bowl is 5 !
or, 5 ∗ 4 ∗ 3 ∗ 2 ∗ 1 = 1 2 0
That's it!! :-)
the formula applied in this question is n! <BR>so, the answer is 5! = (5 x 4 x 3 x 2 x 1)= 120
Many different order of 5 different ingredients is permutation of 5
5 ! = 5 × 4 × 3 × 2 × 1 5 ! = 1 2 0
P n = n ! P 5 = 5 ! P 5 = 1 2 0
itis just 5.4.3.2.1=120
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For the first ingredient you put in the bowl, you have 5 different choices.
Now we have 4 ingredients to put in the bowl. For each of the 5 initial situations we have 4 choices each of what the second ingredient could be. So now we have 5 × 4 = 2 0 possibilities.
Now we have 3 ingredients to put in the bowl. For each of the 2 0 previous situations we have 3 choices each of what the third ingredient could be. So now we have 2 0 × 3 = 6 0 possibilities.
Now we have 2 ingredients to put in the bowl. For each of the 6 0 previous situations we have 3 choices each of what the third ingredient could be. So now we have 6 0 × 2 = 1 2 0 possibilities.
Now we have 1 ingredient to put in the bowl. We have no choice but to put it into the bowl. So we still have 1 2 0 possibilities.
The result is an equation like this: 5 × 4 × 3 × 2 × 1 = 1 2 0 , or better put, 5 ! = 1 2 0 .
Whichever one of these 1 2 0 orders we choose, let's hope it tastes yummy!