Let's Begin the Craze for Inorganic

Chemistry Level 4

Now I am gonna post a inorganic blast off Series. I see that my questions are encouraged by all of you so that's increasing my desire to make more new original questions. So here is the first question (Starting with a simpler one). Let's see who will post the solution first.

That is X which is added to E!

Enter your answer as $M(\alpha) + M(\delta) - M(\beta) - M(\gamma)$ .

Where $M(X)$ represents molecular weight of X.

This is a part of my set Inorganic Fun

30 16 32 60 -4 0 28 14

2 solutions

Marc Fernández
Jun 25, 2017

$A = Cu$

$B = NO_2$

$C = N_{2}O_{5}$

$D = NaNO_3$

$E = NaNO_2$

$F = Na$

$G = Na^+(am) + e^- (am)$

$H = NaOH$

$X = NaNH_2$

$Y = H_2$

$\alpha = N_2$

$\beta = N_{2}O$

$\gamma = NO$

$\delta = NO_2$ .

$4Zn(s) + 10HNO_{3} (aq) \longrightarrow NH_{4}NO_{3}(aq) + 4Zn(NO_{3})_{2}(aq) + 3H_{2}O(l)$

Then how can beta be N2O??

Aniswar S K - 3 years, 7 months ago

Hey , 2no + h2s ------> n2o + h2o + s

Please Please - 2 years, 3 months ago

Sumanth R Hegde
Apr 14, 2017

$\alpha = N_{2}$

$\beta = N_{2}O$

$\gamma = NO$

$\delta = NO_2$

Let's Begin the Craze for Inorganic

This is a part of my set Inorganic Fun

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