Find the range of value of for which the expression can take all real values for .
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A standard approach will be to find the derivative of the above expression. If a function is strictly increasing or strictly decreasing along the real line then the function takes all real values.
In this case the derivative comes out to be ( 4 x − λ ) 2 8 x 2 − 4 λ x + 5 λ − 1 2
We notice that the numerator part is an concave up parabola and the denominator is always greater than zero in the provided domain.
Thus the derivative must be greater than zero.
8 x 2 − 4 λ x + 5 λ − 1 2 > 0
This implies that it's discriminant should be less than zero.
1 6 λ 2 − 3 2 ( 5 λ − 1 2 ) < 0
( λ − 4 ) ( λ − 6 ) < 0
λ ∈ ( 4 , 6 )