Lets cut out plane !

Consider 25 straight lines in a plane which are no 2 are parallel and no 3 are concurrent. How many regions do these lines divide the plane ?

362 426 326 462

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2 solutions

Pranjal Jain
Nov 29, 2014

Think about one line. It divides in 2 parts. Now about 2 lines. They divide a plane in 4 parts. 3 lines? 7 parts. 4? 11 parts. This might give an idea that number of parts must be a x 2 + b x + c ax^2+bx+c where x is number of lines! ( x 2 x^2 because differece forms AP). By plugging in x=1,2,3, we will get a = 1 2 , b = 1 2 , c = 1 a=\frac{1}{2},\ b=\frac{1}{2},\ c=1

Hence max number of parts in which n lines may divide a plane are n 2 + n 2 + 1 \frac{n^{2}+n}{2}+1 .

By substituting n = 25 n=25 , we will get number of parts to be 326 \boxed{326}

Please explain why did you take a quadratic expression to represent the number of parts .

Kudou Shinichi - 6 years, 5 months ago

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The quadratic equation is able to give no. Of divided regions where x represents no. of lines . Its just like a series

Utsav Singhal - 6 years, 5 months ago
Rayyan Shahid
Jan 24, 2015

There can be a simple formula for this 2 n + ( n 2 ) ( n 1 ) 2 2n+ \frac{(n-2)(n-1)}{2} where n n is the no of lines substituting n with 25 25 we get 50 + 23 × 24 2 50 + \frac{23 \times 24}{2} = 50 + 276 = 50 + 276 = 326 =326

Hey genius can you please tell me how to deal such probs?????

Ankit Kumar Jain - 6 years ago

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