Let's do some calculus! (38)

Calculus Level 5

S 1 = 3 4 n = 1 1 n 2 S 2 = n = 0 1 ( 1 + 2 n ) 2 S 3 = 3 2 n = 1 ( 1 ) n n 2 S 4 = 2 ( n = 0 ( 1 ) n 1 + 2 n ) 2 \begin{aligned} S_1 &=& \dfrac 34 \displaystyle \sum_{n=1}^{\infty} \dfrac{1}{n^2} \\ S_2 &=& \displaystyle \sum_{n=0}^{\infty} \dfrac{1}{{(1+2n)}^2} \\ S_3 &=& -\dfrac 32 \displaystyle \sum_{n=1}^{\infty} \dfrac{{(-1)}^n}{n^2} \\ S_4 &=& 2 {\left( \displaystyle \sum_{n=0}^{\infty} \dfrac{{(-1)}^n}{1+2n} \right)}^2 \end{aligned}

Choose the correct order of the infinite sums listed above.


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S 1 > S 2 > S 3 > S 4 S_1 > S_2 > S_3 > S_4 S 3 > S 2 > S 1 = S 4 S_3 > S_2 > S_1 = S_4 S 1 < S 2 < S 3 < S 4 S_1 < S_2 < S_3 < S_4 S 4 = S 2 > S 3 = S 1 S_4 = S_2 > S_3 = S_1 All sums are diverging S 1 = S 2 = S 3 = S 4 S_1 = S_2 = S_3 = S_4 S 1 > S 2 = S 3 = S 4 S_1 > S_2 = S_3 = S_4

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