Let's do some calculus! (53)

Calculus Level 5

Let f : R R f: \mathbb{R} \mapsto \mathbb{R} be a function continuous in [ 1 , 6 ] [1,6] and differentiable in ( 1 , 6 ) (1,6) such that f ( 1 ) = 3 f(1) = 3 and f ( 6 ) = 5 f(6) = 5 . It is given that 1 6 ( f ( x ) ) 2 d x = 11 \displaystyle \int_1^6 (f(x))^2 \,dx = 11 , then what is the minimum value of

( 1 6 x 2 ( f ( x ) ) 2 d x ) ( 1 6 ( f ( x ) ) 2 d x ) \large \left( \int_1^6 x^2 (f(x))^2 \,dx \right) \left( \int_1^6 (f'(x))^2 \,dx \right)


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The answer is 4225.

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