Let's Find the Maximum Value !

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Let S S = x s e c x 12 x 2 + 3 + 12 x 2 t a n x 2 \frac { x sec x }{ 12x^{2} + 3 +12x^{2} tan x^{2} } for 0 < < x x < < π \pi

The maximum value of S S can be written as a b \frac {a}{b} , where a a is relatively prime with b b

Then, What is the value of a a + b b ?


The answer is 13.

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