Let's improve in Chemistry

Chemistry Level 5

A 3.00 g 3.00\text{ g} sample containing F e X 3 O X 4 \ce{Fe3O4} , F e X 2 O X 3 \ce{Fe2O3} and an inert impure substance, is treated with excess of K I \ce{KI} solution in presence of dilute H X 2 S O X 4 \ce{H2SO4} . The entire ion is converted into F e X 2 + \ce{Fe^{2+}} along with liberation of Iodine. The resulting solution is diluted to 100 mL 100\text{ mL} . A 20 mL 20\text{ mL} of the dilute solution requires 11.0 mL 11.0\text{ mL} of 0.5 M 0.5\text{ M} N a X 2 S X 2 O X 3 \ce{Na2S2O3} to reduce iodine present. A 50 mL 50\text{ mL} of dilute solution, after complete extraction of Iodine requires 12.80 mL 12.80\text{ mL} of 0.25 M 0.25\text{ M} K M n O X 4 \ce{KMnO4} solution in dilute H X 2 S O X 4 \ce{H2SO4} medium for oxidation of F e X 2 + \ce{Fe^{2+}} . Calculate the percentage of F e X 2 O X 3 \ce{Fe2O3} in the mixture.


The answer is 49.33.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Suhas Sheikh
Jun 12, 2018

Consider Fe3O4 to be. A coordinated mixture of FeO and Fe2O3 (In 1:1 ratio) Next use Law of chemical equivalences to form 2 relations in x(amount of Fe3O4) and y(amount of Fe2O3) Using the 2 given info regarding iodometry and permanganate titrations To find x and y separately That finishes the problem

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...