Let's integrate

Calculus Level 3

x 2 + 1 x 3 + 3 x d x \large \displaystyle \int \frac{x^2+1}{x^3+3x} \, dx

If the value of above expression is in the form 1 A ln x A + A x + C \frac{1}{A} \ln | x^A+Ax | +C , find A A .


The answer is 3.

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1 solution

Rishabh Jain
Feb 14, 2016

d ( x 3 + 3 x ) = 3 ( x 2 + 1 ) d x \Large d(x^3+3x)=3(x^2+1)dx Hence integration simplifies to: 1 3 d ( x 3 + 3 x ) x 3 + 3 x \Large \dfrac{1}{3} \int \dfrac{d(\color{#007fff}{x^3+3x})}{\color{#007fff}{x^3+3x}} = 1 3 ln ( x 3 + 3 x ) + C \Large =\dfrac{1}{\color{#D61F06}{3}}\ln(x^{\color{#D61F06}{3}}+\color{#D61F06}{3}x)+C Hence A = 3 \huge A=\boxed{3}

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