If has three terms which are then how many terms does will have?
This problem is original.
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We can Do this Question using Logic or by using Properties of Multinomial Thm 1st Method : logic We can see that each term is Basically getting multiplied by 26 letters so Total Terms = 2 6 × 2 6 = 6 7 6 But only terms like a 2 , b 2 . . z 2 are Unique, Terms like a b , b a and z a , a z will merge Subtracting the unique 26 terms from total terms , we need to divide the rest by 2 We get : Terms = 2 6 7 6 − 2 6 = 3 2 5 Now add the unique terms Back in terms , we get our Total Terms : 3 2 5 + 2 6 = 3 5 1
2nd Method : Multinomial From a Property of Binomial Thm. Coefficient of a term in ( a + b + c + d + . . . ) n is : n 1 ! × n 2 ! × n 3 ! × n 4 ! × . . . . n ! × a n 1 × b n 2 × c n 3 × d n 4 × . . . . Where n 1 + n 2 + n 3 + n 4 + ⋯ = n and 0 ≤ n 1 , n 2 , n 3 , n 4 , . . . ≤ n In this case n 1 + n 2 + n 3 + ⋯ + n 2 6 = 2 Total Number of terms = Number of Integral Solutions of this equation ⟹ ( 2 6 − 1 2 + 2 6 − 1 ) ⟹ ( 2 5 2 7 ) ⟹ Ans : 2 2 7 × 2 6 = 3 5 1