-digit number such that the ratio of this number to the sum of its digits, is minimum.
Find the
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Let the 3-digit number be 100x+10y+z where x, yand z are the hundredth, tenth and ones digit respectively.
We have to minimize the ratio :
It can be simplified to :
For the above ratio to be minimum, we have to simultaneously minimize 99x + 9y and maximize x+y+z. So z has to be 9 (largest digit) to make the sum of x+y+z as maximum. For x and y, we have to consider both numerator and denominator. Since x is multiplied by 99 in the numerator so x has a more dominant effect on numerator than denominator. So x should be minimum so as to make 99x minimum. So x has to be 1 (x can't be 0 as it is the hundredth digit of a 3-digit number). So the number is of the form 1y9. Try all the 10 possibilities i.e. 109,119,129,..........., 199. The minimum ratio is found if the number is 199.