Revise Chemistry

Chemistry Level 3

There is a univalent metal M M

Lets say we have a FCC lattice of M(only univalent one is present here). If the side lenght of the cubic lattice being a = 1 A o a=1 A^{o} . Density of the cubic lattice is 4 g / c c 4 g/cc .

If 6 m g 6 mg of metal M M is treated with excess C l X \ce{Cl-} we get M C l \ce{MCl} . [ M C l \ce{MCl} is non volatile]

Now this metal chloride prepared is placed inside 100 g 100g of ethylene glycol solution which causes a elevation in boiling point.

If the K b = 2.2 6 o C k g / m o l K_{b}=2.26 ^{o}C kg/mol of the solvent and the boiling point of the pure solvent is T b = 19 7 o C T_{b}=197^{o}C .

Take T 1 T_{1} (in K) to be the boiling point of the mixture of the above solution. Take T = [ T 1 ] T=[T_{1}] ([.] is box function).

Also if elevation in boiling point is δ T b \delta T_{b} . Take T 2 = [ 26 × δ T b ] T_{2}=[26\times\delta T_{b}] ( K K )

In ethylene glycol medium , the dissociation of MCl takes place like

M C l M X + + C l X ( K e q = 10 ) \ce{MCl <=>} \ce{M+} + \ce{Cl-} \space \space \space (K_{eq}=10)

(Assume molarity \approx molality) .

Enter value of T + T 2 T+T_{2} . (in Kelvin)

Assume

  • Avogadro's Number N A = 6 × 1 0 23 N_{A}=6 \times 10^{23} .


The answer is 481.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...