Level 1 integral

Calculus Level 2

0 π ( sin x + cos x ) 2 d x = ? \large \int _0^\pi(\sin x+\cos x)^2\ dx =?


The answer is 3.1415.

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1 solution

Chew-Seong Cheong
Feb 22, 2019

I = 0 π ( sin x + cos x ) 2 d x = 0 π ( sin 2 x + 2 sin x cos x + cos 2 x ) d x = 0 π ( 1 + 2 sin ( 2 x ) ) d x = x cos ( 2 x ) 2 0 π = π 3.142 \begin{aligned} I & = \int_0^\pi (\sin x + \cos x)^2 \ dx \\ & = \int_0^\pi \left(\sin^2 x + 2\sin x \cos x + \cos^2 x \right) \ dx \\ & = \int_0^\pi \left(1 + 2\sin (2x) \right) \ dx \\ & = x - \frac {\cos (2x)}2 \ \bigg|_0^\pi \\ & = \pi \approx \boxed{3.142} \end{aligned}

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