Level 1 Operation: Deceiving Value

We know that any number $a$ to the power $0$ is equal to $1$ , i.e., $a^0=1$ .

Now, it is said that ---->

$a=2^{34-34}+9 \quad \text{and} \quad b=a$

$a=2^0+9 \quad \text{and} \quad b=a$

$a=1+9=10 \quad \text{and} \quad b=a=10$

Now, $\large d=\frac{a}{b}=\frac{10}{10}=1$

So, $\large C=\frac{\sqrt{ab}}{d}=\frac{\sqrt{10\times 10}}{1}=\sqrt{100}=\boxed{\pm 10}$

But, since here only the positive answer is accepted as the correct answer, so the correct answer $=\boxed{10}$

So, if $a=b$ and $d=\frac{a}{b}$ ,

then, $d=\frac{a}{a}=1$

hence, $C=\frac{\sqrt{ab}}{d}=\frac{\sqrt{a^2}}{1}=a$

therefore, $C=2^{34-34}+9=2^0+9=1+9=10\leftarrow$

Very very simple.

34-34=0

Simple so far???? Good.

2 to the power of zero=1

(Any number to the power of zero is 1, don't ask me how.)

1+9=10

See!! I told you it was easy!!!

a=10

b=a, or b=10

d=a/b

d=10/10

d=1

Look at how simple this is!!

c= square root of ab/d

c= square root of 10*10/1

c=square root of 100/1

c=10/1

C=10

$2^{34-34} = 2^{0} = 1$ , thus $a = 1 + 9 = 10$

$b = a$ , so $b = 10$

$\frac{a}{b} = \frac{10}{10} = 1$ , thus $d = 1$

$\sqrt{ab} = \sqrt{10 \times 10} = 10$

$d = 1$ , so $C = \frac{10}{1} = 10$

$a=2^{34-34}+9$

$a=2^{0}+9$

$a=1+9$

$a=10$

$b=10$

$d=\frac{a}{b}$

$d=\frac{10}{10}$

$d=1$

$C=\frac{\sqrt{ab}}{d}$

$C=\frac{\sqrt{100}}{1}$

$C=\boxed{10}$

a = 10 ,, b = 10 ,, d =1 ,, c = ((a*b) ^ (1/2)) / d,, therefore.. (100 ^ (1/2)) / 1 = 10..

given a=b therfore a=2^0 + 9 = 10 a=10 on solving C=a therefore C=10

c=b/b/a c=1/1/a and a=2*0+9=1=9=10 so c=10

a=1+9=10=b d=a/b=a/a=1 C=a/1=10/1=10

a=10 b=a=10 d=1 c=10/1=10

where a=2^34-34 + 9. anything power zero is equal to 1.so 34-34=0. a=1+9=10; b=a:d=a/b. to find c=10/1=10.