Liars 1

Logic Level 2

Fourteen people are sitting in a circle. Each one of them either always lies or always says the truth.(This does not mean for all of them to have the same alignment) Each of them says "Both my neighbors are liars". What is the largest amount of liars possible?


The answer is 9.

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1 solution

Richard Desper
May 21, 2020

Let us number the people around the table from 1 1 to 14 14 . Let t 1 , t 2 , , t k t_1, t_2, \ldots, t_k be the positions of the k k truth tellers.
Without loss of generality, t 1 = 1 t_1=1 .

Notice that we cannot have three liars in a row, thus t i + 1 t i + 3 t_{i+1} \leq t_{i}+3 for all i i . Thus t k 3 k 2. t_k \leq 3k -2.

But also t k 12 t_k \geq 12 , or there will be at least three consecutive liars after the last truth-teller before we reach the first truth teller again.

So 12 3 k 2 12 \leq 3k -2 , i.e. 3 k 14 3k \geq 14 , or k 14 / 3 k \geq 14/3 .

Since k k is an integer, k 5 k \geq 5 . There must be at least 5 5 truth-tellers, so there can be at most 9 9 liars.

This bound of 9 9 can be reached with t i = 3 i 2 t_i = 3i - 2 .

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