Lift off!

An airplane accelerates down a runway at 3.2 m / s 2 3.2m/s^2 for 32.8 seconds until it finally lifts off. How far did it travel on the runway in meters?


The answer is 1721.34.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Simple.

Given that, a = 3.2 m / s 2 a=3.2m/s^2 t = 32.8 s t=32.8s u = 0 m / s u=0m/s Distance Travelled = d You know, d = u t + 1 2 a t 2 d=ut+\frac{1}{2}at^2 = 1 2 × 3.2 × 32. 8 2 m =\frac{1}{2}\times 3.2\times 32.8^2 m = 1721.344 m =1721.344 m

Really a piece of cake isn't it?

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...